Which phrase describes the function of a buffer?
To excrete weak acids.
To secrete hydrogen ions.
To convert strong acids to weak acids.
To convert ammonia to ammonium ions.
The Correct Answer is C
Choice A rationale:
Buffers do not excrete weak acids; instead, they help regulate the pH of bodily fluids by preventing drastic changes in acidity or alkalinity.
Choice B rationale:
Buffers do not secrete hydrogen ions. In fact, buffers can either absorb or release hydrogen ions to maintain a stable pH.
Choice C rationale:
To convert strong acids to weak acids is the correct answer. Buffers are substances that can neutralize both acids and bases, helping to maintain a stable pH in a solution. They achieve this by accepting hydrogen ions from strong acids or donating hydrogen ions to strong bases, converting them into weaker acids or bases, respectively.
Choice D rationale:
Buffers do not convert ammonia to ammonium ions. This conversion is a part of the body's acid-base regulation system, but it is not the primary function of buffers.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
Choice A rationale:
Serotonin is a neurotransmitter that plays a role in mood regulation, sleep, and other functions in the body. It is not a component that forms an adhesive bridge between platelets and vascular subendothelial structures in the clotting process.
Choice B rationale:
Platelet factor III is not a component that forms an adhesive bridge between platelets and vascular subendothelial structures in the clotting process. Platelet factor III is not widely recognized in the context of clotting; it is more commonly referred to as tissue factor and is involved in the extrinsic pathway of coagulation.
Choice C rationale:
Von Willebrand factor (VWF) is a protein that plays a crucial role in hemostasis. It forms an adhesive bridge between platelets and vascular subendothelial structures, particularly at sites of vascular injury. VWF helps platelets adhere to the injured vessel wall, leading to the formation of a stable blood clot. This process is essential for preventing excessive bleeding. A deficiency or dysfunction in VWF can lead to von Willebrand disease, a bleeding disorder characterized by prolonged bleeding times.
Choice D rationale:
Adenosine diphosphate (ADP) is a molecule released by platelets when they are activated. ADP helps in the aggregation of platelets, but it does not directly form an adhesive bridge between platelets and vascular subendothelial structures.
Correct Answer is D
Explanation
The correct answer is choice d. pH = 7.52, PaCO2 = 24 mm Hg, PaO2 = 85 mm Hg, and HCO3 = 24 mEq/L.
Rationales:
Choice A rationale:
- pH = 7.46: This value is slightly alkalotic.
- PaCO2 = 44 mm Hg: This is within the normal range (35-45 mm Hg), indicating that the respiratory system is not contributing to alkalosis.
- PaO2 = 95 mm Hg: This is a normal oxygen level.
- HCO3 = 36 mEq/L: This is elevated, indicating metabolic alkalosis rather than respiratory alkalosis.
Choice B rationale:
- pH = 7.27: This value is acidic, indicating acidosis.
- PaCO2 = 70 mm Hg: This is elevated, indicating respiratory acidosis.
- PaO2 = 80 mm Hg: This is slightly low, indicating mild hypoxemia.
- HCO3 = 26 mEq/L: This is within the normal range, indicating no metabolic compensation.
Choice C rationale:
- pH = 7.30: This value is acidic, indicating acidosis.
- PaCO2 = 35 mm Hg: This is within the normal range, indicating that the respiratory system is not contributing to acidosis.
- PaO2 = 70 mm Hg: This is low, indicating hypoxemia.
- HCO3 = 20 mEq/L: This is low, indicating metabolic acidosis.
Choice D rationale:
- pH = 7.52: This value is alkalotic.
- PaCO2 = 24 mm Hg: This is low, indicating respiratory alkalosis.
- PaO2 = 85 mm Hg: This is a normal oxygen level.
- HCO3 = 24 mEq/L: This is within the normal range, indicating no metabolic compensation.
Choice D corresponds with respiratory alkalosis because the pH is alkalotic, and the PaCO2 is low, indicating that the respiratory system is causing the alkalosis. The HCO3 is within the normal range, showing no metabolic compensation.
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