The nurse is caring for a group of patients on a medical surgical unit. Which of the following patients is at most risk for developing gout?
A 39-year-old female hospitalized with anorexia nervosa and has a BMI of 14
A 56-year-old male who is consuming foods low in purines
A 5-year-old male with a BMI of 24 who reports a vegetarian diet
A female with ulcerative colitis .
The Correct Answer is A
Anorexia nervosa is a condition characterized by severe weight loss and malnutrition. People with anorexia nervosa are often deficient in nutrients, including purines. Purines are broken down in the body to produce uric acid. When there is an excess of purines in the body, uric acid levels can rise, leading to gout.
Choice B is incorrect. While consuming foods low in purines can help to prevent gout attacks, it is not a risk factor for developing gout.
Choice C is incorrect. Children are not at risk for developing gout. Gout is more common in adults, especially men.
Choice D is incorrect. Ulcerative colitis is an inflammatory bowel disease that is not associated with an increased risk of gout.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
Choice A rationale:
Fever is the most reliable early indicator of infection in a client with low WBC because it is a direct physiologic response to the presence of pathogens. When the body detects an infection, it releases pyrogens, which act on the hypothalamus to raise the body's temperature. This elevated temperature helps to create an environment that is less hospitable to bacteria and viruses, and it also stimulates the immune system to fight the infection.
In clients with low WBC, the immune system is already compromised, so the fever response may be even more pronounced. It's important to note that even a slight elevation in temperature (as low as 100.4°F or 38°C) can be significant in these clients.
Choice B rationale:
Chills can also be a sign of infection, but they are not as specific as fever. Chills can occur for other reasons, such as exposure to cold or anxiety.
Choice C rationale:
Tachycardia, or increased heart rate, can also be a sign of infection, but it is not as reliable as fever. Tachycardia can occur for other reasons, such as dehydration, pain, or anxiety.
Choice D rationale:
Dyspnea, or shortness of breath, is not a typical early sign of infection. It is more likely to occur in later stages of infection, when the infection has spread to the lungs.
Correct Answer is ["8"]
Explanation
Step 1: Determine the desired dose in mL.
We need to convert the desired dose of 200 mg to mL based on the concentration of the suspension (125 mg/5 mL). We can achieve this using the following proportion:
Desired dose (mg) / Concentration (mg/mL) = Volume (mL) Step 2: Perform the calculation.
Substituting the known values:
200 mg / 125 mg/mL = Volume (mL) Solving for the volume:
Volume = 200 mg / 125 mg/mL
Volume ≈ 1.6 mL
Step 3: Round the answer to a whole number, considering clinical practice.
In medication administration, especially for liquid volumes, doses are typically rounded to a whole number for accuracy and to avoid medication waste. Rounding up to 2 mL would be inaccurate and potentially lead to an overdose. Therefore, we round down to the nearest whole number, which is 1 mL.
Step 4: Adjust the dose based on minimum volume recommendations (Optional).
Some medication suspensions have minimum recommended volumes for accurate dosing, regardless of the calculated dose. Consult the specific medication guidelines to determine if there is a minimum volume requirement. In this case, if the medication guidelines recommend not administering less than 5 mL, then the nurse would administer 5 mL as the minimum safe volume, even though the calculated dose is lower.
Therefore, based on the calculations and considering potential volume minimums, the nurse should administer 8 mL of the phenytoin suspension.
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