A patient's health history is suggestive of inflammatory bowel disease. Which of the following would suggest Crohn's disease, rather than ulcerative colitis, as the cause of the patient's signs and symptoms?
Severe diarrhea
Involvement of the rectal mucosa
An absence of blood in stool
A pattern of distinct exacerbations and remissions
The Correct Answer is D
Choice A reason:
Severe diarrhea can be a symptom of both Crohn's disease and ulcerative colitis and does not specifically indicate one over the other.
Choice B reason:
Involvement of the rectal mucosa is more indicative of ulcerative colitis rather than Crohn's disease, as Crohn's disease can affect any part of the digestive tract.
Choice C reason:
The presence or absence of blood in stool is not a definitive indicator of either Crohn's disease or ulcerative colitis, as both conditions can involve bleeding.
Choice D reason:
This statement is correct. A pattern of distinct exacerbations and remissions is more characteristic of Crohn's disease, whereas ulcerative colitis often presents with continuous, chronic symptoms.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
Choice A reason:
This statement is not directly related to the client's use of bisacodyl tablets. It addresses irregular bowel movements in a general sense.
Choice B reason:
Decreasing fiber intake is not a recommended approach, especially for an older adult who may benefit from a balanced diet with adequate fiber.
Choice C reason:
This is the correct answer. Excessive use of laxatives, including bisacodyl, can lead to electrolyte imbalances. Bisacodyl is a stimulant laxative that can cause excessive fluid loss and potentially
disrupt electrolyte levels.
Choice D reason:
While chronic use of laxatives can lead to various complications, including potential harm to the rectal mucosa, this choice is not the most appropriate response to the client's current situation.
Correct Answer is ["1.9"]
Explanation
Calculation:
Dosage ordered = 7.6 mg
Drug concentration = 4 mg/mL
7.6 mg / 4 mg/mL = 1.9 mL
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