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A patient is receiving an IV of 500 mL of D5W (dextrose 5% in water).
How many grams (g) of dextrose are contained in this IV solution?

A.

10g

B.

25g

C.

50g

D.

100g

Answer and Explanation

The Correct Answer is B

Dextrose 5% in water (D5W) is an IV fluid that contains **5 grams of dextrose** per 100 mL of water². To calculate how many grams of dextrose are in 500 mL of D5W, you can use a simple proportion:

5 g / 100 mL = x g / 500 mL

Cross-multiply and solve for x:

x = (5 g * 500 mL) / 100 mL

x = 25 g

Therefore, there are **25 grams of dextrose** in 500 mL of D5W.


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Related Questions

Correct Answer is C

Explanation

the correct rate to administer the maintenance dose is 50 mL/hr.

Step 1: Determine the concentration of magnesium sulfate in the solution.

  • There are 40 grams of magnesium sulfate in 1 liter of solution.
  • 1 liter = 1000 mL.

Step 2: Calculate the concentration in grams per mL.

  • 40 grams ÷ 1000 mL = 0.04 grams per mL.
  • Result: 0.04 grams per mL.

Step 3: Determine the required dose per hour.

  • The physician ordered 2 grams per hour.

Step 4: Calculate the volume of solution needed to provide 2 grams of magnesium sulfate.

  • Required dose (2 grams) ÷ concentration (0.04 grams per mL) = volume in mL.
  • 2 grams ÷ 0.04 grams per mL = 50 mL.
  • Result: 50 mL.
  • The calculated rate is 50 mL/hr.

the correct rate to administer the maintenance dose is 50 mL/hr.

Correct Answer is A

Explanation

To calculate the gt/min flow rate, we need to determine the total number of drops and divide it by the total time in minutes.

First, let's convert the volume from liters to milliliters:

1 L = 1000 mL

Next, we need to determine the total number of drops. This can be calculated using the drop factor and the volume of the solution:

Total drops = Volume (mL) * Drop factor

= 1000 mL * 15 gt/mL

= 15000 gt

Now, we need to calculate the flow rate in gt/min. We divide the total drops by the total time in minutes: Flow rate = Total drops / Total time (min)

= 15000 gt / 360 min

≈ 41.67 gt/min (rounded to the nearest whole number)

Therefore, the correct answer is:

a. 41.6 gt/min

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