A nurse is reviewing the laboratory findings of a client who experienced an acute myocardial infarction 6 days ago. Which of the following laboratory values should the nurse expect to remain elevated at this time?
Troponin T
Creatinine phosphokinase
Myoglobin
Creatinine kinase-MB
The Correct Answer is A
A. Troponin T: Troponin T remains elevated for 10 to 14 days after a myocardial infarction. This protein is highly specific for cardiac muscle injury and is used to confirm myocardial infarction.
B. Creatinine phosphokinase: Creatinine phosphokinase (CPK) typically returns to normal levels within 3 days after a myocardial infarction, so it would no longer be elevated at this point.
C. Myoglobin: Myoglobin rises early after a myocardial infarction but is not specific to heart muscle and returns to normal within 24 hours, so it would not be elevated at this time.
D. Creatinine kinase-MB: Creatinine kinase-MB (CK-MB) usually returns to normal levels within 2 to 3 days after a myocardial infarction, so it is unlikely to still be elevated 6 days later.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
A. Obtain a blood sample. While obtaining a blood sample to check cardiac enzyme levels is important for diagnosing myocardial injury, it is not the priority over oxygen therapy, given the client’s shortness of breath and cyanosis.
B. Insert the IV catheter. IV access is important for administering fluids and medications, but it is not the first priority in this scenario where the client is experiencing respiratory distress.
C. Initiate oxygen therapy. The client shows signs of hypoxia (shortness of breath and cyanosis), and oxygen is crucial for stabilizing oxygen levels and preventing further deterioration of cardiac and respiratory function.
D. Attach the leads for a 12-lead ECG. Attaching the leads for an ECG is essential to evaluate the client's cardiac status, but it is not the most urgent action in the presence of cyanosis and respiratory distress.
Correct Answer is ["100"]
Explanation
Flow rate (gtt/min) =(Volume ×Drop factor)/60
= (100 ×60)/60
Flow rate (gtt/min)= 100 gtt/min
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