A nurse is reviewing the laboratory data of a client following a hemodialysis treatment. The nurse should expect to find a decrease in which of the following laboratory values?
Calcium
Potassium
Protein
RBC count
The Correct Answer is B
Choice a) is incorrect because calcium levels are not directly affected by hemodialysis. Calcium is a mineral that is important for bone health, blood clotting, and muscle contraction. Hemodialysis does not remove calcium from the blood, but it may cause low calcium levels if the dialysate fluid has a lower concentration of calcium than the blood.
Choice b) is correct because potassium levels are decreased by hemodialysis. Potassium is an electrolyte that is essential for nerve and muscle function, especially the heart. Hemodialysis removes excess potassium from the blood, which can build up in people with kidney failure and cause irregular heartbeats, muscle weakness, or even cardiac arrest.
Choice c) is incorrect because protein levels are not decreased by hemodialysis. Protein is a macromolecule that is composed of amino acids and performs various functions in the body, such as building and repairing tissues, transporting substances, and regulating processes. Hemodialysis does not remove protein from the blood, but it may cause low protein levels if the client has a poor diet or loses protein through other means, such as urine or wounds.
Choice d) is incorrect because RBC count is not decreased by hemodialysis. RBCs are red blood cells that carry oxygen throughout the body. Hemodialysis does not remove RBCs from the blood, but it may cause low RBC count if the client has anemia, which is a common complication of kidney failure. Anemia can be caused by reduced production of erythropoietin (a hormone that stimulates RBC production), iron deficiency, or blood loss.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
Choice A: Troponin I is a laboratory test that the nurse should anticipate the provider to prescribe. Troponin I is a protein that is released into the blood when the heart muscle is damaged. Troponin I levels are elevated in clients who have acute myocardial infarction (AMI), which is a heart atack caused by a blockage of blood flow to the heart. Chest pressure and shortness of breath are common signs and symptoms of AMI. Troponin I is a specific and sensitive marker of cardiac injury and can help diagnose AMI and guide treatment.
Choice B: Aspartate aminotransferase (AST) is not a laboratory test that the nurse should anticipate the provider to prescribe. AST is an enzyme that is found in various tissues, such as the liver, heart, skeletal muscle, and kidneys. AST levels are elevated in clients who have liver damage, hepatitis, cirrhosis, or alcohol abuse. AST levels can also be elevated in clients who have AMI, but they are not as specific or sensitive as troponin I. AST is not a reliable indicator of cardiac injury and can be influenced by other factors.
Choice C: B-type natriuretic peptide (BNP) is not a laboratory test that the nurse should anticipate the provider to prescribe. BNP is a hormone that is secreted by the heart when it is stretched or overloaded. BNP levels are elevated in clients who have heart failure, which is a condition in which the heart cannot pump enough blood to meet the
body's needs. Shortness of breath can be a sign of heart failure, but chest pressure is not. BNP is not a specific or sensitive marker of cardiac injury and can be influenced by other factors.
Choice D: Lipase is not a laboratory test that the nurse should anticipate the provider to prescribe. Lipase is an enzyme that is produced by the pancreas and helps digest fats. Lipase levels are elevated in clients who have pancreatitis, which is an inflammation of the pancreas. Pancreatitis can cause abdominal pain, nausea, vomiting, and fever. Chest pressure and shortness of breath are not signs of pancreatitis. Lipase is not a specific or sensitive marker of cardiac injury and has no relation to AMI.
Correct Answer is A
Explanation
The correct answer is: A. Elective cardioversion
Choice A reason:
Elective cardioversion is a medical procedure that is used to restore a normal heart rhythm in patients experiencing certain types of arrhythmias, including ventricular tachycardia (VT), when they are stable. It involves the delivery of a controlled electric shock to the heart, which is synchronized with the heart's electrical activity to convert the abnormal rhythm back to a normal sinus rhythm. This procedure is typically performed when VT is not causing hemodynamic instability and the patient is not in immediate danger.
Choice B reason:
Defibrillation is an emergency treatment for life-threatening cardiac arrhythmias, particularly ventricular fibrillation (VF) or pulseless ventricular tachycardia. It involves delivering a high-energy electric shock to the heart unsynchronized to the heart's electrical cycle, aiming to reset the heart's electrical state and allow it to reestablish an effective rhythm. In the scenario provided, where the patient is experiencing VT but not VF, defibrillation would not be the first line of action unless the VT deteriorates into VF or the patient becomes pulseless.
Choice C reason:
CPR, or cardiopulmonary resuscitation, is a lifesaving technique useful in many emergencies, including heart attack or near drowning, in which someone's breathing or heartbeat has stopped. In the case of VT, if the patient is conscious and has a pulse, CPR is not indicated. CPR would only be necessary if the patient's heart stops beating (cardiac arrest) as a result of the VT.
Choice D reason:
Radiofrequency catheter ablation is a procedure used to treat some types of arrhythmias, including VT, by destroying the area of heart tissue that is causing the abnormal heart rhythm. This treatment is generally considered when medication is ineffective or not tolerated, or in recurrent VT. It is not typically the first line of treatment in an acute setting where the patient is stable and experiencing VT.
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