A nurse is preparing to administer clindamycin palmitate 225 mg PO to a client.
Available is clindamycin palmitate oral suspension 75 mg/5 mL.
How many ml’s should the nurse administer?
The Correct Answer is ["15"]
Step 1 is to determine the amount of clindamycin palmitate in each mL of the oral suspension. This is done by dividing the total amount of clindamycin palmitate in 5 mL by 5. So, 75 mg ÷ 5 mL = 15 mg/mL.
Step 2 is to calculate the volume of oral suspension needed to deliver 225 mg of clindamycin palmitate. This is done by dividing the desired dose by the amount of clindamycin palmitate per mL. So, 225 mg ÷ 15 mg/mL = 15 mL.
Therefore, the nurse should administer 15 mL of clindamycin palmitate oral suspension.
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Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["15"]
Explanation
Step 1 is to determine the amount of clindamycin palmitate in each mL of the oral suspension. This is done by dividing the total amount of clindamycin palmitate in 5 mL by 5. So, 75 mg ÷ 5 mL = 15 mg/mL.
Step 2 is to calculate the volume of oral suspension needed to deliver 225 mg of clindamycin palmitate. This is done by dividing the desired dose by the amount of clindamycin palmitate per mL. So, 225 mg ÷ 15 mg/mL = 15 mL.
Therefore, the nurse should administer 15 mL of clindamycin palmitate oral suspension.
Correct Answer is B
Explanation
Choice B rationale
A respiratory rate of 20 breaths per minute is within the normal range for an adult, indicating that the patient’s respiratory status is stable. This would be an important indicator of the effectiveness of nursing care in a patient admitted with a lower respiratory infection.
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