A nurse is preparing to administer cefazolin 250 mg via intermittent IV bolus every 8 hr. Available is cefazolin 500 mg vial.
The package insert instructs to add 2 mL of sterile water to yield a concentration of 225 mg/mL and then add to 50 mL of 0.9% sodium chloride.
How many mL of cefazolin should the nurse add to the 50 mL of 0.9% sodium chloride? (Round the answer to the nearest tenth.
Use a leading zero if it applies.
Do not use a trailing zero.). mL. .
The Correct Answer is ["1.1"]
Step 1: Calculate the volume of cefazolin needed for a 250 mg dose.
Volume of cefazolin = 250 mg ÷ 225 mg/mL = 1.11 mLStep 2: Round the answer to the nearest tenth.
1.11 mL rounded to the nearest tenth is 1.1 mL.Therefore, the nurse should add 1.1 mL of cefazolin to the 50 mL of 0.9% sodium chloride.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["2 mL"]
Explanation
Step 1 is to determine the amount of medication needed. The order is for 30 mg and the available medication is 15 mg/mL. So, we calculate 30 mg ÷ 15 mg/mL = 2 mL. So the correct answer is 2 mL.
Correct Answer is ["57 mL"]
Explanation
Step 1 is to convert the client’s weight from pounds to kilograms. We know that 1 kg is approximately 2.2 lb. So, the client’s weight in kg is 178 lb ÷ 2.2 lb/kg = 80.91 kg. Step 2 is to calculate the total dose of acetylcysteine. The total dose is 140 mg/kg × 80.91 kg = 11327.4 mg. Step 3 is to calculate the volume to administer. The volume is 11327.4 mg ÷ 200 mg/mL = 56.637 mL.
So, the correct answer is 57 mL after rounding to the nearest whole number.
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