A nurse is preparing to administer cefazolin 250 mg via intermittent IV bolus every 8 hr. Available is cefazolin 500 mg vial.
The package insert instructs to add 2 mL of sterile water to yield a concentration of 225 mg/mL and then add to 50 mL of 0.9% sodium chloride.
How many mL of cefazolin should the nurse add to the 50 mL of 0.9% sodium chloride? (Round the answer to the nearest tenth.
Use a leading zero if it applies.
Do not use a trailing zero.). mL. .
The Correct Answer is ["1.1"]
Step 1: Calculate the volume of cefazolin needed for a 250 mg dose.
Volume of cefazolin = 250 mg ÷ 225 mg/mL = 1.11 mLStep 2: Round the answer to the nearest tenth.
1.11 mL rounded to the nearest tenth is 1.1 mL.Therefore, the nurse should add 1.1 mL of cefazolin to the 50 mL of 0.9% sodium chloride.
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Related Questions
Correct Answer is ["3"]
Explanation
Step 1 is to determine the total amount of medication needed. The doctor ordered 300 mg of phenytoin and each capsule contains 100 mg. So, we divide the total amount ordered by the amount per capsule: 300 mg ÷ 100 mg/capsule = 3 capsules.
So, the correct answer is 3 capsules.
Correct Answer is ["1.9"]
Explanation
Step 1 is to convert the client’s weight from pounds to kilograms since the dosage is prescribed in mcg/kg. Given that 1 kg = 2.2 lb, we calculate:
165 lb ÷ 2.2 = 75 kg
Step 2 is to calculate the volume of naloxone to be administered. The prescribed dosage is 10 mcg/kg, so we first determine the total dose:
10 mcg/kg × 75 kg = 750 mcg
Next, we convert the available concentration of naloxone from mg/mL to mcg/mL:
0.4 mg/mL × 1000 mcg/mg = 400 mcg/mL
Now, we calculate the required volume by dividing the total dose by the concentration:
750 mcg ÷ 400 mcg/mL = 1.875 mL
Rounding to the nearest tenth, the correct amount to administer is 1.9 mL.
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