A nurse is educating a pregnant client about the Contraction Stress Test (CST).
Which statement accurately describes a negative CST?
No contractions were induced during the test.
Late decelerations of the FHR were observed with at least 50% of contractions.
The FHR remained stable throughout the test.
The client experienced mild uterine cramping during the tes.
The Correct Answer is C
This means that the baby’s heart rate did not slow down after the contractions induced by oxytocin, which is a sign of normal fetal well-being.
A negative CST is normal and desirable.
Choice A is wrong because no contractions were induced during the test.
This means that the test was inconclusive and could not assess the baby’s response to stress.
Choice B is wrong because late decelerations of the FHR were observed with at least 50% of contractions.
This means that the baby’s heart rate slowed down and stayed slow after the contractions, which is a sign of fetal distress and hypoxia.
A positive CST is abnormal and concerning.
Choice D is wrong because the client experienced mild uterine cramping during the test.
This is not a relevant factor for interpreting the CST results, which depend on the FHR patterns.
Uterine cramping can be a side effect of oxytocin administration or nipple stimulation.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
This result suggests that the baby has a low risk of having a genetic disorder or a neural tube defect.
Choice B is wrong because a high level of AFP indicating a neural tube defect would be greater than 2 MoM.
Choice C is wrong because a low level of AFP indicating a potential chromosomal abnormality would be less than 0.5 MoM.
Choice D is wrong because an inconclusive result, requiring further evaluation, would depend on other factors such as ultrasound findings and maternal age.
MoM stands for multiples of the median, which is a way of comparing the AFP level of a pregnant person to the average level for their gestational age.
Values between 0.5 and 2.49 MoM are considered normal.
Correct Answer is C
Explanation
The patient should wear loose-fitting clothing and lie supine on an examination table.
This is because loose-fitting clothing allows easy access to the abdomen and lying supine helps relax the abdominal muscles.
The patient should also avoid food and drinks for 8 to 12 hours before the test, as undigested food can interfere with the sound waves and affect the image quality.
Choice A is wrong because a full bladder is not necessary for an abdominal ultrasound, unless the patient is pregnant or has a pelvic condition.
A transvaginal ultrasound is a different type of ultrasound that uses a probe inserted into the vagina to examine the reproductive organs.
Choice B is wrong because tight-fitting clothing can restrict the movement of the ultrasound probe and make it harder to get a clear image.
Lying prone (on the stomach) can also tense up the abdominal muscles and obscure the organs.
Choice D is wrong because lying prone can have the same disadvantages as choice B. Additionally, wearing loose-fitting clothing does not mean that the patient can eat or drink anything before the test, as this can affect the results.
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