A nurse is caring for a client with a pheochromocytoma. Which assessment finding will the nurse expect for this client?
Decreased pulse
Elevated blood pressure
Cold intolerance
Decreased respiratory rate
The Correct Answer is B
A. A decreased pulse is not typically associated with pheochromocytoma. This condition is characterized by the excessive release of catecholamines, which usually leads to an increased heart rate.
B. Pheochromocytoma is a tumor of the adrenal medulla that causes excessive secretion of catecholamines, leading to episodic or sustained hypertension. Elevated blood pressure is a hallmark symptom of this condition.
C. Cold intolerance is more commonly associated with hypothyroidism and is not a typical finding in pheochromocytoma.
D. Decreased respiratory rate is not characteristic of pheochromocytoma; instead, clients may experience symptoms such as palpitations, sweating, and headaches due to the elevated catecholamine levels.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["A","C","D","E"]
Explanation
A. The nurse should inform the client that if the stockings are too tight, they may impair blood flow rather than prevent it, which could increase the risk of complications such as pressure sores or circulatory issues.
B. While the stockings should be removed periodically, removing them only once daily for 30 minutes may not be sufficient for skin inspection and care. Best practice usually involves removing them more frequently, such as every 8 hours, to check for skin integrity.
C. Proper skin hygiene and regular assessment should be performed each time the stockings are removed to ensure there is no irritation, breakdown, or circulatory impairment.
D. Antiembolism stockings are designed to be worn both in and out of bed to maintain consistent pressure on the legs and reduce the risk of deep vein thrombosis (DVT).
E. Proper measuring of the leg is crucial to ensure that the stockings fit correctly, providing the necessary compression without being too tight or too loose.
Correct Answer is ["1370"]
Explanation
To calculate the total output of the client, the nurse would add together all the measured outputs. The client voided 400 mL at 1100 and 350 mL at 1430, which totals 750 mL. The closed chest drainage system shows an increase from 155 mL to 175 mL, indicating an output of 20 mL. The NG tube has 575 mL in the drainage container. Additionally, 25 mL was emptied from the Jackson-Pratt drainage tube. Adding these amounts together (750 mL + 20 mL + 575 mL + 25 mL), the total output recorded by the nurse should be 1370 mL.
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