The nurse is caring for client who is diagnosed with hypertrophic cardiomyopathy. Which medical Intervention should the nurse anticipate for this client for the complications of dysrhythmias?
Insertion of a cardioverter-defibrillator
A medication regimen that includes nitrates
Immediate cardiac transplantation
Insertion of a drug eluting stent
The Correct Answer is A
A) Insertion of a cardioverter-defibrillator:
Hypertrophic cardiomyopathy (HCM) is a condition characterized by abnormal thickening of the heart muscle, particularly the septum, which can lead to obstruction of blood flow and contribute to the development of arrhythmias. The most concerning arrhythmias in HCM include ventricular tachycardia and ventricular fibrillation, both of which can lead to sudden cardiac arrest. A cardioverter-defibrillator (ICD) is a device that monitors the heart's rhythm and can deliver a shock to restore normal rhythm in the event of a life-threatening arrhythmia.
B) A medication regimen that includes nitrates:
Nitrates are vasodilators commonly used in the treatment of conditions like angina and heart failure. However, nitrates are generally avoided in patients with hypertrophic cardiomyopathy because they can exacerbate the condition by decreasing preload and increasing the outflow tract obstruction due to the thickened heart muscle.
C) Immediate cardiac transplantation:
Cardiac transplantation is a treatment for end-stage heart failure, typically in patients who have not responded to medical or surgical treatments. While hypertrophic cardiomyopathy can lead to heart failure, it is not the first line treatment for dysrhythmias or complications from the disease.
D) Insertion of a drug-eluting stent:
Drug-eluting stents are used to prevent restenosis (narrowing) of coronary arteries after percutaneous coronary intervention (PCI) in patients with coronary artery disease (CAD). However, hypertrophic cardiomyopathy is not caused by coronary artery disease.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
A) Urine output of 0.5-1 mL/kg/hr:
This is a positive outcome during fluid resuscitation for burn patients. Adequate urine output is a key indicator of proper renal perfusion and fluid balance. A urine output of 0.5-1 mL/kg/hr is considered optimal for burn patients during the first 24-48 hours of resuscitation. It suggests that the kidneys are receiving sufficient blood flow and that the patient is responding appropriately to the fluids being administered.
B) Serum sodium level 149 mEq/L (normal 135-145):
A serum sodium level of 149 mEq/L is high and indicates hypernatremia, which is a common complication of excessive fluid resuscitation, particularly with the use of crystalloids. Hypernatremia can lead to cerebral edema, altered mental status, and other severe complications. Therefore, this finding would suggest improper fluid management and would not be considered a positive outcome.
C) Blood pressure 82/54:
A blood pressure of 82/54 is hypotensive, which is concerning in a burn patient. Hypotension indicates inadequate tissue perfusion, potentially leading to shock and organ failure. While low blood pressure may occur in the initial stages of resuscitation due to the rapid shifts in fluid, a sustained low blood pressure is not a positive outcome.
D) Heart rate 124 beats per minute:
A heart rate of 124 beats per minute is tachycardic and suggests that the patient is compensating for hypovolemia or inadequate circulatory volume, possibly due to insufficient fluid resuscitation. Although an elevated heart rate may occur as a compensatory mechanism in the initial stages of burn resuscitation, sustained tachycardia indicates ongoing volume depletion or inadequate perfusion and is not an ideal outcome.
Correct Answer is ["A","D","E"]
Explanation
A) If there is a QRS complex after each P wave:
This is an important consideration when identifying a cardiac rhythm. The P wave represents atrial depolarization, and the QRS complex represents ventricular depolarization. In a normal sinus rhythm, every P wave is followed by a QRS complex, which confirms that the impulse originating in the SA node is being conducted properly through the atrioventricular (AV) node and into the ventricles. The presence of a QRS after every P wave helps confirm normal conduction and rhythm.
B) The rate using only a 3-second strip:
While the heart rate is an essential part of the rhythm assessment, using only a 3-second strip is not the most accurate method for determining the rate. Typically, a 6-second strip is used to estimate the rate, multiplying the number of R-R intervals by 10 to obtain the heart rate. A 3-second strip can be used for quick estimates but may lead to inaccurate calculations of the heart rate.
C) The duration of the U waves:
The U wave is often a normal variant seen in the ECG and is not always present. If it is visible, its duration is typically not a primary focus in rhythm interpretation unless there are concerns about electrolyte imbalances, such as hypokalemia. The U wave is not a core factor to consider when identifying the overall rhythm.
D) If the P waves are present:
The presence of P waves is important for identifying the rhythm, particularly when differentiating between sinus rhythms (normal) and non-sinus rhythms (such as atrial arrhythmias). In normal sinus rhythm, P waves should be present, reflecting atrial depolarization initiated by the SA node. The absence of P waves can indicate atrial fibrillation, atrial flutter, or other arrhythmias.
E) If the P-P and R-R distances are equal:
This is crucial in identifying a regular rhythm. The P-P interval refers to the distance between successive P waves (atrial depolarization), and the R-R interval refers to the distance between successive R waves (ventricular depolarization). In normal sinus rhythm or regular rhythms, both the P-P and R-R intervals should be equal, indicating that the atrial and ventricular rhythms are consistent. If they are unequal, it suggests an irregular rhythm (e.g., atrial fibrillation).
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