The client tells the nurse, "My physician told me that I had a non-ST elevation myocardial infarction (NSTEMI). " I thought all heart attacks were the same. Can you explain this to me?" The nurse's best response to the client's question would be: "NSTEMI is
similar to the angina attacks you had in the past."
a condition characterized by coronary arteries vasodilating."
a term used to describe an irregular heartbeat."
is a less severe type of heart attack compared to STEMI."
The Correct Answer is D
A. Similar to the angina attacks you had in the past:
This response is not entirely accurate. Angina refers to chest pain that occurs when the heart's demand for oxygen exceeds its supply, usually due to partial blockage of the coronary arteries. NSTEMI (non-ST elevation myocardial infarction) is different from angina in that it involves actual heart muscle injury or damage due to partial or intermittent blockage of a coronary artery, whereas angina does not cause permanent heart muscle damage. Therefore, describing NSTEMI as similar to past angina attacks would be misleading.
B. A condition characterized by coronary arteries vasodilating:
This is incorrect. NSTEMI occurs due to a partial blockage or narrowing of the coronary arteries, usually caused by a blood clot that forms around a ruptured atherosclerotic plaque. The blockage restricts blood flow to the heart muscle, causing injury or infarction. Vasodilation (the widening of blood vessels) is not a characteristic of NSTEMI; in fact, it is the constriction or blockage of the coronary arteries that leads to this type of heart attack.
C. A term used to describe an irregular heartbeat:
This is incorrect. NSTEMI is not related to an irregular heartbeat or arrhythmia directly. While arrhythmias (irregular heartbeats) can occur as a result of a heart attack, NSTEMI specifically refers to a type of heart attack that is not accompanied by the characteristic ST-segment elevation seen on an electrocardiogram (ECG) in a STEMI (ST-elevation myocardial infarction). It indicates a partial blockage of a coronary artery and is generally less severe than STEMI.
D. Is a less severe type of heart attack compared to STEMI:
This is the most accurate response. NSTEMI is a type of heart attack that is often considered less severe than STEMI, but still involves heart muscle injury. The difference between NSTEMI and STEMI lies in the ECG findings: STEMI involves a full-thickness myocardial infarction with a significant blockage of the artery, as indicated by ST-segment elevation on an ECG. In NSTEMI, there is a partial blockage or temporary decrease in blood flow, and the ST-segment does not elevate on the ECG, but biomarkers (like troponin) are elevated, indicating heart muscle damage. NSTEMI is often less severe in terms of the extent of damage compared to STEMI, but it still requires urgent treatment to prevent further complications.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["20"]
Explanation
Step-by-Step Solution:
Calculate the volume of medication to administer.
The available medication is 125 mg/5 mL.
We need to administer 500 mg.
To find the volume, we can set up a proportion:
125 mg / 5 mL = 500 mg / x mL
Cross-multiplying:
125x = 500 x 5
Solving for x:
x = (500 x 5) / 125 = 20 mL
Correct Answer is B
Explanation
A. Partially compensated metabolic alkalosis:
Metabolic alkalosis is characterized by elevated bicarbonate levels (HCO3), but in this case, the HCO3 is elevated (29 mEq/L), which suggests alkalosis. However, the PaCO2 is elevated at 47 mmHg, which is more consistent with a respiratory problem. A fully or partially compensated metabolic alkalosis would show a normal or low PaCO2 (due to respiratory compensation). Therefore, this option does not fit the ABG results.
B. Partially compensated respiratory acidosis: In this case, the pH is 7.17, which is low and indicates acidosis. The PaCO2 is 47 mmHg, which is elevated (normal range: 35-45 mmHg), indicating that the respiratory system is contributing to the acidosis. The HCO3 is 29 mEq/L, which is elevated (normal range: 22-26 mEq/L), suggesting a compensatory response from the kidneys to retain bicarbonate in an attempt to buffer the acidosis. Since the pH is still below normal and has not yet returned to the normal range (7.35-7.45), this suggests that the compensation is partial and the primary issue is respiratory acidosis.
C. Fully compensated metabolic alkalosis:
This answer is incorrect because metabolic alkalosis is not the primary disturbance here. Also, for a condition to be fully compensated, the pH would need to be within the normal range (7.35-7.45). Since the pH is 7.17, the condition is not fully compensated.
D. Fully compensated respiratory acidosis:
For fully compensated respiratory acidosis, the pH should be within the normal range, as the kidneys would have fully compensated for the elevated PaCO2. Since the pH is 7.17, this is a sign of partial compensation, not full compensation. Therefore, this option is incorrect.
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