Aspirin is administered to the client experiencing an MI because of its:
Antipyretic action
Antiplatelet action
Analgesic action
Antithrombotic action
The Correct Answer is B
Choice A rationale:
Antipyretic action refers to the ability to reduce fever. While aspirin does have antipyretic properties, this is not the primary reason it is administered during an MI. Fever is not a characteristic symptom of MI, and reducing fever would not directly address the underlying cause of the MI, which is the formation of a blood clot in a coronary artery.
Choice B rationale:
Antiplatelet action is the ability to prevent platelets from clumping together and forming blood clots. This is the crucial mechanism by which aspirin helps in the setting of an MI.
During an MI, a blood clot forms in a coronary artery, blocking blood flow to the heart muscle. This blockage can cause severe damage to the heart muscle, leading to chest pain, shortness of breath, and potentially life-threatening complications.
Aspirin irreversibly inhibits the enzyme cyclooxygenase (COX), which is essential for platelet aggregation. By blocking COX, aspirin prevents platelets from sticking together and forming new clots. This can help to:
Limit the size of the existing clot in the coronary artery.
Prevent the formation of additional clots that could further block blood flow.
Allow for better blood flow to the heart muscle, reducing damage and improving outcomes.
Choice C rationale:
Analgesic action refers to the ability to relieve pain. While aspirin does have analgesic properties, this is not the primary reason it is administered during an MI. Pain relief is an important aspect of managing MI symptoms, but it does not directly address the underlying cause of the MI, which is the blood clot.
Choice D rationale:
Antithrombotic action is a broader term that encompasses any action that prevents or reduces blood clot formation. Aspirin's antiplatelet action is a specific type of antithrombotic action. However, it's important to note that aspirin does not directly dissolve existing clots; it primarily prevents new clots from forming.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
The correct answer is A. Electrocardiogram.
Choice A rationale:
Electrocardiogram (ECG) is the priority diagnostic procedure for a suspected myocardial infarction (MI) due to several compelling reasons:
Rapidity: An ECG can be performed quickly and easily at the bedside, providing immediate results within minutes. This swiftness is crucial in the context of MI, where time is of the essence to initiate appropriate treatment and salvage viable heart tissue.
Sensitivity: The ECG is highly sensitive in detecting the electrical changes that occur during an MI. It can identify characteristic ST-segment elevation or depression, T wave inversions, and other abnormalities that strongly suggest myocardial ischemia or infarction.
Specificity: While not perfectly specific for MI, the ECG can often distinguish it from other conditions that may cause chest pain, such as pericarditis or pulmonary embolism. This diagnostic differentiation is crucial for guiding appropriate management.
Non-invasiveness: The ECG is a non-invasive procedure that does not involve any needles, catheters, or exposure to radiation. This makes it a safe and readily accessible test, even for patients who may be hemodynamically unstable or have other medical conditions.
Cost-effectiveness: The ECG is a relatively inexpensive diagnostic tool compared to other imaging modalities like echocardiography or cardiac angiography. This cost-effectiveness makes it a valuable first-line test in evaluating potential MI, allowing for efficient resource allocation.
Rationales for other choices:
Choice B (Papercut): This is not a relevant diagnostic procedure for MI and is therefore incorrect.
Choice C (Cardiac Angiogram): While cardiac angiography can definitively visualize coronary artery blockages, it is an invasive procedure that carries risks and requires specialized facilities and personnel. It is typically reserved for cases where the diagnosis remains uncertain after non-invasive testing or when intervention is planned.
Choice D (Echocardiogram): Echocardiography can assess heart function and detect structural abnormalities, but it is less sensitive than ECG for the early electrical changes of MI. It may be used as an adjunct test to provide additional information, but it is not the priority procedure in the initial evaluation.
Correct Answer is B
Explanation
Choice B rationale:
LDL (low-density lipoprotein) cholesterol is often referred to as "bad" cholesterol. It contributes to the buildup of plaque in the arteries, which narrows the arteries and can lead to coronary artery disease (CAD). CAD is a major risk factor for heart attack and stroke.
HDL (high-density lipoprotein) cholesterol is often referred to as "good" cholesterol. It helps to remove LDL cholesterol from the arteries and transport it back to the liver, where it can be broken down and removed from the body. Therefore, a high HDL level is protective against heart disease.
An elevated LDL level and a lowered HDL level are both associated with an increased risk of CAD. This is because the elevated LDL level contributes to plaque buildup, while the lowered HDL level means that there is less "good" cholesterol available to remove the "bad" cholesterol from the arteries.
Therefore, the statement "Increased LDL and decreased HDL increase my risk of coronary artery disease" indicates an understanding of the significance of these cholesterol levels.
Choice A rationale:
This statement is incorrect. An increased LDL level will actually increase the amount of cholesterol deposited on the artery walls.
Choice C rationale:
This statement is also incorrect. A decreased HDL level will decrease the amount of cholesterol moved away from the artery walls.
Choice D rationale:
This statement is incorrect. Increased LDL has the potential to increase, not decrease, the risk of heart disease.
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