A nurse is preparing to administer ziprasidone 175 mg IM to a patient. Available is ziprasidone 20 mg/mL. How many mL should the nurse administer?
(Round the answer to the nearest tenth. Use a leading zero if it applies. Do not use a trailing zero.)
The Correct Answer is ["8.8"]
Step 1: The dose to be administered is175 mg of ziprasidone.
Step 2: The available ziprasidone injection has a concentration of20 mg/mL. This means that for every 1 mL of the solution, there are 20 mg of ziprasidone.
Step 3: To find out how many mL should be administered, we divide the dose by the concentration. So, 175 mg ÷ 20 mg/mL = 8.75 mL.
Step 4: Round the answer to the nearest tenth. So, 8.75 mL rounds to8.8 mL.
The nurse should administer 8.8 mL of ziprasidone injection
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is ["150"]
Explanation
Step 1: Start with 0.15 g of desipramine.
Step 2: Use the conversion factor 1 g = 1000 mg. So, to convert g to mg, we multiply by 1000.
Step 3: Calculate 0.15 g × 1000 = 150 mg.
So, 0.15 g is equivalent to 150 mg.
Correct Answer is ["2"]
Explanation
Step 1: The dose to be administered is50 mg of chlorpromazine.
Step 2: The available chlorpromazine injection has a concentration of25 mg/mL. This means that for every 1 mL of the solution, there are 25 mg of chlorpromazine.
Step 3: To find out how many mL should be administered, we divide the dose by the concentration. So, 50 mg ÷ 25 mg/mL = 2 mL.
The nurse should administer 2 mL of chlorpromazine injection.
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