A nurse is preparing to administer mannitol 0.2 g/kg IV bolus over 5 min as a test dose to a client who has severe oliguria. The client weighs 198 lb. What is the amount in grams the nurse should administer?
(Round the answer to the nearest whole number. Use a leading zero if it applies. Do not use a trailing zero.)
The Correct Answer is ["18"]
The client weighs 198 lb, which is equivalent to (198 ÷ 2.2 = 90kg.
Therefore, the amount of mannitol for the test dose is 0.2 g/kg x 90 kg = 18 g.
The nurse should administer 18 g of mannitol IV bolus over 5 min as a test dose to the client who has severe oliguria.
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