A nurse is preparing to administer mannitol 0.2 g/kg IV bolus over 5 min as a test dose to a client who has severe oliguria. The client weighs 198 lb. What is the amount in grams the nurse should administer?
(Round the answer to the nearest whole number. Use a leading zero if it applies. Do not use a trailing zero.)
The Correct Answer is ["18"]
The client weighs 198 lb, which is equivalent to (198 ÷ 2.2 = 90kg.
Therefore, the amount of mannitol for the test dose is 0.2 g/kg x 90 kg = 18 g.
The nurse should administer 18 g of mannitol IV bolus over 5 min as a test dose to the client who has severe oliguria.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is A
Explanation
A. Correct. The nurse should turn off the CPM machine during mealtime, as it can interfere with the client's ability to eat and drink comfortably. The nurse should also turn off the CPM machine when transferring or repositioning the client, or when performing wound care or other interventions on the affected leg.
B. Incorrect. The nurse should maintain the client's affected hip in a neutral position, as external rotation can cause malalignment of the prosthesis and impair healing. The nurse should use pillows or wedges to support the leg and prevent rotation or abduction of the hip joint.
C. Incorrect. The nurse should not instruct the client how to adjust the CPM settings, as this can compromise the prescribed range of motion and speed of the device. The nurse should follow the provider's orders and check with them before making any changes to the CPM settings. The nurse should also monitor the client's pain level and administer analgesics as needed to facilitate compliance with the therapy.
D. Incorrect. The nurse should not store the CPM machine under the client's bed when not in use, as this can pose a safety hazard and damage the equipment. The nurse should place the CPM machine on a stable surface near the bed and ensure that it is plugged into a grounded outlet and has adequate battery backup in case of power failure.
Correct Answer is D
Explanation
A. This is incorrect because weight gain is not expected in clients who have COPD, as they often have difficulty eating and digesting food due to dyspnea and fatigue.
B. This is incorrect because a decrease in anteroposterior diameter of the chest is not typical of COPD, as the condition causes hyperinflation and air trapping in the lungs, leading to an increase in chest size and a barrel-shaped appearance.
C. This is incorrect because HCO3 24 mEq/L is within the normal range for blood bicarbonate levels, which are 22 to 26 mEq/L. Clients who have COPD often have chronic respiratory acidosis, which stimulates the kidneys to retain bicarbonate and increase its levels in the blood to compensate for the low pH.
D. This is correct because pH 7.31 indicates acidosis, which is common in clients who have COPD due to impaired gas exchange and accumulation of carbon dioxide in the blood.
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