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A nurse is preparing to administer lorazepam 0.05 mg/kg IM 2 hr prior to surgery to a client who weighs 138 lb. If the available lorazepam injection is 2 mg/mL, how many mL should the nurse administer? .
Answer and Explanation

The Correct Answer is ["1.57 "]

Step 1: Calculate the dose of lorazepam. The doctor ordered 0.05 mg/kg, so 0.05 mg/kg × 62.73 kg (138 lb ÷ 2.2 lb/kg) = 3.14 mg.

Step 2: Calculate the volume of lorazepam injection to administer. The available lorazepam injection is 2 mg/mL, so 3.14 mg ÷ 2 mg/mL = 1.57 mL. The nurse should administer 1.57 mL of lorazepam injection.


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Related Questions

Correct Answer is ["0.4 "]

Explanation

The nurse should administer 0.4 mL of morphine per dose. Here’s the calculation: Step 1: The total dosage required is 4 mg.

Step 2: Each mL of the injection contains 10 mg of morphine.

Step 3: So, the volume to be administered is 4 mg ÷ 10 mg/mL = 0.4 mL.

Correct Answer is ["10 "]

Explanation

Step 1: We need to find out how many mL of cefaclor oral suspension the nurse should administer per dose.

Given:

The doctor’s order is 500 mg of cefaclor.

The available cefaclor oral suspension is 250 mg/5 mL.

Step 2: We set up a proportion to find out the volume of the oral suspension that contains 500 mg of cefaclor.

Let’s denote the volume we are looking for as X mL. So, we have:

250 mg : 5 mL = 500 mg : X mL

Step 3: We cross-multiply and solve for X. 250 mg × X mL = 500 mg × 5 mL

Step 4: We divide both sides by 250 mg. X mL = (500 mg × 5 mL) ÷ 250 mg

Step 5: We calculate X.

X = (500 mg × 5 mL) ÷ 250 mg = 10 mL

So, the nurse should administer 10 mL of the cefaclor oral suspension per dose.

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