A nurse is preparing to administer dexamethasone 0.5 mg/kg/day IM to divide equally every 6 hr to a client who weighs 132 lb. Available is dexamethasone 4 mg/mL. How many mL should the nurse administer per dose? (Round the answer to the nearest tenth. Use a leading zero if it applies. Do not use a trailing zero.)
The Correct Answer is ["1.9"]
To calculate the dose of dexamethasone, we need to convert the client's weight from pounds to kilograms. One pound is equal to 0.454 kg, so 132 lb is equal to 132 x 0.454 = 59.928 kg. The prescribed dose is 0.5 mg/kg/day, so the daily dose is 0.5 x 59.928 = 29.964 mg. This dose is divided equally every 6 hours, so the dose per administration is 29.964 / 4 = 7.491 mg. The concentration of the drug is 4 mg/mL, so the volume per administration is 7.491 / 4 = 1.873 mL. Rounded to the nearest tenth, the nurse should administer 1.9 mL per dose.
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Related Questions
Correct Answer is ["167"]
Explanation
To calculate the infusion rate for the IV pump, we need to divide the total volume of the solution (250 mL) by the infusion time (90 min). This gives us:
250 mL / 90 min = 2.778 mL/min
To convert this to mL/hr, we need to multiply by 60 min/hr. This gives us: 2.778 mL/min x 60 min/hr = 166.667 mL/hr
To round this to the nearest whole number, we look at the tenths place and see that it is 6, which is equal to or greater than 5, so we round up and drop the rest of the digits. This gives us:
167 mL/hr
Therefore, the nurse should set the IV pump to deliver 167 mL/hr.
Correct Answer is ["200"]
Explanation
To answer this question, we need to calculate the infusion rate of the IV pump. The formula for infusion rate is:
Infusion rate (mL/hr) = Volume (mL) / Time (hr)
We are given the volume of the solution, which is 50 mL, and the time of administration, which is 15 minutes or 0.25 hours. Plugging these values into the formula, we get:
Infusion rate (mL/hr) = 50 mL / 0.25 hr
Infusion rate (mL/hr) = 200 mL/hr
Therefore, the nurse should set the IV pump to deliver 200 mL/hr. This is the answer to the question.
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