A nurse is caring for a newborn with hyperbilirubinemia who is receiving phototherapy.
Which of the following actions should the nurse take?
Apply lotion to the newborn’s skin before phototherapy.
Remove the newborn from phototherapy every 4 hours.
Cover the newborn’s eyes with a mask during phototherapy.
Place the newborn on a radiant warmer during phototherapy.
The Correct Answer is C
This is because phototherapy exposes the newborn to a special blue-to-green light that lowers the serum bilirubin level by transforming it into water-soluble isomers that can be eliminated without liver conjugation. However, this light can also damage the newborn’s eyes and cause retinal injury or blindness, so it is important to protect them with a mask.
Choice A is wrong because applying lotion to the newborn’s skin before phototherapy can interfere with the light penetration and reduce the effectiveness of the treatment.
It can also cause skin irritation or allergic reactions.
Choice B is wrong because removing the newborn from phototherapy every 4 hours can interrupt the continuous exposure to the light and delay the reduction of bilirubin levels.
The newborn should only be removed from phototherapy for feeding, diaper changes, and physical examination.
Choice D is wrong because placing the newborn on a radiant warmer during phototherapy can increase the risk of dehydration, hyperthermia, and skin burns.
The newborn should be monitored for temperature and fluid balance during phototherapy and kept in a crib or bassinet with a blanket.
Nursing Test Bank
Naxlex Comprehensive Predictor Exams
Related Questions
Correct Answer is C
Explanation
This is because breastfeeding frequently can help the newborn pass more stools, which contain bilirubin, and reduce the risk of jaundice.
Choice A is wrong because supplementing breastfeeding with glucose water can reduce the amount of breast milk intake and increase the risk of jaundice.
Choice B is wrong because exposing the newborn to natural sunlight for short periods has not been proven to be effective in preventing or treating jaundice.
Moreover, sunlight can cause sunburn and dehydration in newborns.
Choice D is wrong because it includes choices A and B, which are incorrect.
Physiologic jaundice is a common and harmless condition that occurs in newborns due to the immature liver function and increased breakdown of red blood cells.It causes yellow discoloration of the skin and eyes due to the accumulation of bilirubin, a yellow pigment of red blood cells.Physiologic jaundice usually appears between the second and fourth day after birth and resolves within one to two weeks.Normal ranges of bilirubin levels vary depending on the age, gestational age, and health status of the newborn, but generally they are below 5 mg/dL (86 micromol/L) at term.
Correct Answer is D
Explanation
Elevated direct bilirubin level: Pathologic jaundice is caused by an excessive breakdown of red blood cells due to blood incompatibility or liver disease.
This leads to an increased production of bilirubin, which is a yellow pigment that results from the breakdown of heme.
Bilirubin can be either unconjugated (indirect) or conjugated (direct), depending on whether it is bound to a protein called albumin or not.
Unconjugated bilirubin is not water-soluble and cannot be excreted in urine or bile.
It needs to be converted to conjugated bilirubin by the liver, which is water-soluble and can be eliminated from the body.However, if the liver is damaged or overwhelmed by the amount of bilirubin, some of the conjugated bilirubin can leak back into the bloodstream and cause an elevated direct bilirubin level.
• Decreased hematocrit level: Hematocrit is the percentage of red blood cells in the blood.When red blood cells are destroyed due to blood incompatibility or liver disease, the hematocrit level decreases.
This can lead to anemia, which is a condition where the blood does not carry enough oxygen to the tissues.
Positive direct Coombs test: A Coombs test is a blood test that detects antibodies that bind to red blood cells and cause them to clump together and be destroyed.
A direct Coombs test checks for antibodies that are attached to the red blood cells of the newborn.A positive direct Coombs test indicates that there is an immune reaction between the mother’s and the baby’s blood types, which can cause hemolysis (destruction of red blood cells) and jaundice.
Choice A is wrong because it only explains one aspect of pathologic jaundice, but not the other two.
Choice B is wrong because it only explains one aspect of pathologic jaundice, but not the other two.
Choice C is wrong because it only explains one aspect of pathologic jaundice, but not the other two.
Normal ranges for direct bilirubin are 0 to 0.3 mg/dL (0 to 5 mic
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