The graph below represents the amount of rainfall in a particular state by month. Which of the following is the total rainfall for the months May, June, and July?

 

to find the average time the athlete runs in 1 mile, find total time divided by total distance covered in the two runs.

Total distance=5+3=8 miles

Total time=25+15=40 minutes

We now know that the athlete runs 8 miles in 40 minutes, so the time the athlete will run in 1 mile will be:  

In 5 minutes, the athlete runs 1 mile.

From the given estimations, we can find the exact sum after adding the given numbers and see the trend the student utilizes to find their estimates. The actual sum is as follows

26+180=206

115+391=506

497+2024=2521

From the above evaluation, the students round the exact sum to the nearest tens. So, in the problem we need to approximate 545+7501.

545+7501=8046

The exact sum is 8046 and the approximate value after rounding to the nearest tens is 8050.

The length of the unknown side of the rectangle can be found by using the Pythagoras theorem. Letting the unknown side to be x, the labelled rectangle becomes: The unknown length of the triangle is about 16.7 feet.

The length of the unknown side of the rectangle can be found by using the Pythagoras theorem. Letting the unknown side to be x, the labelled rectangle becomes:

The unknown length of the triangle is about 16.7 feet.

The interconversion of yards to feet utilizes the relationship 1 yard =3 feet. Then, 9 yards to ft becomes

                                        t

There, 9 yards is equal to 27 ft.

to convert fraction to percent, multiply the fraction with 100%. Therefore, the percent equivalent of 3/4 is

3/4*100%=75%

Thus, 3/4is equal to 75%.

Here we need to find the actual values of the additions and see the trend the student will use to estimate the given problem. The exact sum is as follows

35+192=227

258+350=608

947+1032=1979

From the above calculations, it is evident that the student rounds up or down the ones place values. So, in the problem we need to approximate 694+7618.

694+7618=8312

We can approximate 8312 based on the provided choices is 8310.

Before we compare the values of the options, we convert the decimals to fractions.

5.4 becomes 54/10

6.25 becomes 625/100

Thus, the set of fractions is 11/2, 54/10, 13/3, 625/100. The least common denominator for 2, 10, 3, and 100 is 300, which we use to compare each options given.

11/2*300=1650

54/10*300=1620

13/3*300=1300

625/100*300=1875

From the above, 1875 is the greatest value which corresponds to 6.25. Therefore, 6.25 is the greatest value of all the choices given.

The best way to visualize the student’s score for each subject is to plot them using a bar graph.

To solve the equation this equation, we use a calculator and find the product as:

3.45 * 0.53= 1.8285

We convert the given word problem into a mathematical expression.

Let the number be x.

Thrice a number = 3x

Twelve less than thrice a number = 3x-12

Thus, the required mathematical expression is 3x-12