The graph below compares the age of car to its value. Which of the following is the age of the car when its value is $12,500?

from the provided table, the first option represents the amount of gas in gallons while the second column shows the distance in miles. Thus, (6, 144) will denote that the car can 144 miles by consuming 6 gallons of a gas.

We extrapolate the values of a line between 10 and 15 on y-axis to meet the curve and drop another line from the intersection of the curve to meet the x-axis and read off the age of the car.

Now, let’s extrapolate in the following diagram

The intersection of the line and the x-axis is between 4 and 5 years. This means that the car is about 4.5 years old. From the options given, the age of the car is more than 3 years old.

Here we are required to find the area of the square of sides 3.1 m. The square is a four-sided figure with each side equal and opposite sides making 90 degrees.

Area of the square =side*side

Side=3.1 m

Area of the square =3.1 m *3.1 m=9.61 m2

Note: 3.1 + 3.1 = 6.2 which is a wrong answer.

In the simple interest, we utilize the following formula to find the simple interest after a period of time in years.

I=P*r*t

I is the interest

P=Principal or initial deposit

r=rate

t=time in years

From the given problem, P=$600, r=6%=6/100=0.06, t=5 years. Then

I=$600*0.06*5=$180

After 5 years, Pat will earn an interest of $180.

Looking at the given trend, it is observed that the price increases with years. From 2008 to 2012, the price is fairly constant but we expect it to be more than $130,000 in the year 2016. The expected price in 2016 is $140,000.

The given ratio of yoghurt to toppings is 4:3, meaning:

Yoghurt : toppings =4 : 3

We are given 4.5 oz of toppings and need to find the amount of yoghurt.

Step 1: Set up the proportion

=

Step 2: Solve for yoghurt

Multiply both sides by 4.5:

yoghurt=43×4.5

yoghurt=4×4.5/3=18/3=6oz

A dependent variable is one that when another variable changes, it also changes. In our case, the insurance premium changes if the age, model, mileage of car changes. Thus, insurance premium is the dependent variable while the other three are independent variable.

to do a comparison of the given data set, we convert the fraction numbers into the approximate decimals.

4/3=1.333

2720=1.35

Now, we have 1.333, 1.35, 1.369, 1.357. These numbers are arranged from the smallest to the largest number, we look at the number in the second decimal place value

1.333 the number in second decimal place value is 3

1.35 the number in third decimal place value is 5

1.369 the number in third decimal place value is 6

1.357 the number in third decimal place value is 5

However, 1.35 and 1.357 have 5 in the second-place vale. We use the ird place value to compare the two number:

1.35 is same as 1.350 and the number in the third-place value is 0

1.357 the number in the third-place value is 7

Now, 0 is less than 7, and thus 1.35 is less than 1.357

Overall, 3 is less than 5, and 5 less than 6 and the provided numbers can be arranged from the smallest to the largest as:

1.333, 1.35, 1.357, 1.369

Thus, the corresponding given numbers organized from the smallest to the largest become:

4/3, 27/20, 1.357, 1.369

The greatest value is 1.369

We convert the given weight in pounds to ounces and find total weight. 1 pound=16 ounces, which we interpret as

Or

Use the second option to convert pounds to ounces

Now, we can ounces to ounces as: 48 oz + 5 oz= 53 oz

Therefore, 3 pounds, 5 ounces is equal to 53 oz

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous data. While a bar graph does just fine even with discrete data.