The graph below represents the amount of rainfall in a particular state by month. Which of the following is the total rainfall for the first 5 months of the year?

In the given problem, we use the calculator to evaluate the product 1.9 * 0.75 = 1.425

We use given information to find how much ammonia is need to make the specified solution.

We are told, one gallon of cleaning solution requires 10oz of ammonia. Expressing this mathematically yields two options:

\(\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\)or\(\frac{1\ gallon\ of\ solution}{10\ oz\ of\ ammonia}\)

Now we find how much ammonia is needed using option two.

\(51\ gallon\ of\ solution\ *\frac{10\ oz\ of\ ammonia}{1\ gallon\ of\ solution}\ =\ 510\ oz\ of\ ammonia\)

From the above equation, gallon of solution will cancel, and oz of ammonia is left.

Therefore, the solution will require 510 oz of ammonia.

We are required to find the percent equivalent of the given fraction.

We multiply 7/8 by 100 to convert it to percent. You convert fraction to percent.

Thus 7/8 is equal to 87.5%.

In this problem, we need to find the amount of gratuity the couple will leave. The gratuity is 16% of the total bill. Before solving the problem, the following are terms and their meaning in percent problems:

• Is means equals
• Of means multiply
• What means unknown (variable)

If we let x be the amount of gratuity, then translating the given problem into a mathematical equation becomes:

Now we evaluate the above equation noting that of means multiply.

So, the value of x=9.376 and to the nearest cent, x=9.38

There, a couple will leave a gratuity of $9.38.

Here we convert between feet and yards. We know 1 yard =3 feet. Then, 27 feet to yards will be:

Thus, 9 yards is equal to 27 ft.

The truck carries a whole cargo which equals 1. If we let the weight of the cargo to be p, then we set up a proportion equation with weight as numerator and fraction of cargo as denominator.

Solve for value of p by cross products

Multiply both sides by 3/2 a reciprocal of 2/3

The truck carries a cargo weighing 795 lb.

Here we need to find the actual values of the additions and see the trend the student will use to estimate the given problem. The exact sum is as follows

35+192227

258+350=608

947+1032=1979

From the above calculations, it is evident that the student rounds up or down the ones place values. So, in the problem we need to approximate 694+7618.

694+7618=8312

We can approximate 8312 based on the provided choices is 8310.

to find the average time the athlete runs in 1 mile; we find total distance and total time the athlete takes in running.

Total distance run by athlete=7+3=10 miles

Total time=45+15 =60 minutes

The athlete runs 10 miles in 60 minutes. For the athlete to cover 1 mile, he will run for a time less than 60 minutes. Thus, in 1 mile, the athlete takes:

So, in 6 minutes, the athlete covers 1 mile.

In this scenario, we use the given scale in the charts to find the number of each coin and selected the right number of coins the student collected.

From the above evaluations, option two is the correct choice.

A whole pizza represents 1, and two friends eat ¼ of the pizza. The remaining fraction of pizza is:

Remaining amount = 

Thus, 3/4 of pizza is left for three friends to share equally.

Now, the other three friends will each get

So, the other three friends will each get 1/4 of the pizza.