Japheth’s uncle is 10 less than three times Japheth’s age. Which of the equations represents Japheth’s uncle’s age (u) as it relates to Japheth’s age (k)?

A dependent variable is one that depends on the independent variable. An independent variable is one that when changed result in a change of another variable.

In this problem, if we change the brand of laptop, tax rate, and memory size, the price of the laptop changes. Thus, the cost of the laptop is the dependent variable.

We follow the order of operations to solve the given expression. The order of operations is PEMDAS:

• Parentheses
• Exponents
• Multiplication and Division (in order from left to right)
• Addition and Subtraction (in order from left to right)

First, we start with the numerator and solve it as follows

[3(6+5*4)]

We start with multiplication in parenthesis, 5*4=20. The expression becomes

[3(6+20)]

Then, we conduct the addition in parenthesis 6+20=26. Then, the expression becomes

[3(26)]=3*26=78

Now, we solve for denominator, which is 26/2=13.

Thus, the expression is reduced into

The expression reduces into 6.

The length of the chair could be appropriately measured in centimeters. Kilometers are used to measure long distances while micrometers could be used to measure the length of small microorganism in microbiology lab. However, milligrams are used to measure the masses of small quantities.

We use the given slope to find the minimum length of the ramp. In this case, slope is the ratio of height to length of the lamp. Thus,

If we let x be the minimum length of the ramp. Then,

Substituting the value of slope into the above equation results in,

Solve for value of x by cross-products

X = 18 Feet

Thus, the minimum length of the ramp needed to provide access to a door that is 1.5 high is 18 feet.

To find the cheapest option, we find the amount the consume will spend for each option given.:

• 2 packs of Orange and 1 pack of Cream Soda will cost $16+$5= $21
• 3 Packs of Orange will cost $16+$12=$28
• 2 packs of Root Beer and 1 pack of Cream Soda will cost 2($15)+$7=$37
• 5 packs of cream Soda will cost 5($7)=$35

From the above evaluation, the cheapest option will cost the consumer $21. Thus, buying 2 packs of Orange and 1 pack of Cream Soda will be cheaper to purchase compared to other options.

Before finding the greatest number from the data set, the numbers need to be in fraction form.

-0.5=-5/10

-1.5=-15/10

The set of numbers becomes -2/3, -5/10, -15/10, -4/9

Now the least common denominator for 3, 10, and 9 is 90, which will be used to multiplied by the given fractions as follows:

-2/3*90=-60

-5/10*90=-45

-15/10*90=-135

-4/9*90=-40

From the above evaluations, the resulting numbers arranged from the smallest to the largest is -135, -60, -45, -40. Thus, the greatest number from the data set is -40, with a corresponding fraction of -4/9.

P-At=-kr

Subtract P on both sides

P-P-At=-kr-P

-At=-kr-P

Divide both sides by -t

-At/-t=(-kr-P)/-t

A=(kr+P)/t

In this task, we use the relation from the given scenario to compare the number of dimes to quarters.

If we let p be number of pennies in the bottle. Then,

Number of quarters in the bottle = 2p

Number of nickels in the bottle = 3p

Number of dimes in the bottle =6(3p)=18p

Now relating dimes to quarters, we have

Thus, there are 9 times as many dimes as quarters in the box.

Here, we are required to find the unit of measuring mass. The SI unit of mass is kilogram but other derived units are grams, milligrams, microgram and more.

A kilogram is a large quantity for measuring heavier objects but grams can used to measure small and light objects such as the mass of the mobile phone. Therefore, gram is the appropriate unit for measuring weight of a mobile phone.

We need to find the radius of the circle in order to find circumference of the circle. If we let r to be radius of the circle, then

Substituting 169π in place of area

Dividing both sides by pi and taking square root on both sides yields

The radius of the circle from the given area is 13 in. and the circumference of the circle is given by the relation: