If x represents the width of a rectangle and length is six less than two times the width, which of the following expressions represents the length of the rectangle in terms of x?

We know that 1 L =1000 mL, which we use to convert between the two units. The conversion fractions of interconverting are:

And

Since we want to end up with millimeters, the second conversion is used in converting L to mL as:

Thus, 3.2 L is equivalent to 3200 mL.

correlations fall into positive, negative, and no correlation. A positive correlation shows that an increase in one variable increase results in an increase on the other variable increases as shown.

A negative correlation scatter plot shows that an increase in one variable results in a decrease on the other one.

The no-correlation scatter plot demonstrates that there is no response between variables. A change in one variable has no effect on the other variable.

Looking at the provided scatter plot, the heights of the students does not have any relationship on the students’ scores. Thus, the type of correlation is no correlation.

Correlation of two variables falls into:

Positive correlation: an increase in one variable causes another variable to increase

Negative correlation: an increase in one variable causes another one to decrease

No correlation: a change in one variable does not cause any response in another variable.

From the given choices

Option a is no correlation

Option b is a negative correlation

Option c is a negative correlation

Option d is a positive correlation

Thus, the correct statement is a.

In this problem, we need to find the amount of gratuity the couple will leave. The gratuity is 16% of the total bill. Before solving the problem, the following are terms and their meaning in percent problems:

• Is means equals
• Of means multiply
• What means unknown (variable)

If we let x be the amount of gratuity, then translating the given problem into a mathematical equation becomes:

So, the value of x=9.376 and to the nearest cent, x=9.38

There, a couple will leave a gratuity of $9.38.

The distribution of the weights of the newborn babies is symmetric meaning the mean, mode, and median are all equal. Thus, the bell-shape curve describes this kind of distribution of weights

When solving percent problems, the following words and their meaning becomes handy.

• Is means equals
• Of means multiply
• What means unknown (variable)

If we let x represent the amount of tip the couple want to leave behind, then

So, the couple will leave a tip of $2.84, which is about $3.00

Before we compare the values of the options, we convert the decimals to fractions.

5.4 becomes 54/10

6.25 becomes 625/100

Thus, the set of fractions is 11/2, 54/10, 13/3, 625/100. The least common denominator for 2, 10, 3, and 100 is 300, which we use to compare each options given.

11/2*300=1650

54/10*300=1620

13/3*300=1300

625/100*300=1875

From the above, 1875 is the greatest value which corresponds to 6.25. Therefore, 6.25 is the greatest value of all the choices given.

: We need to find the total rainfall for the months of May, June, and July using the given graph.

In the month of May, rainfall is between 3 and 4, which is halfway. Therefore, rainfall in May is 3.5 inches

On June, rainfall was 3 inch and on July the rainfall was 2.5 inches. Thus,

Total rainfall=3.5 inches+3 inches+ 2.5 inches=9.0 inches

Here we need to find the actual values of the additions and see the trend the student will use to estimate the given problem. The exact sum is as follows

35+192=227

258+350=608

947+1032=1979

From the above calculations, it is evident that the student rounds up or down the ones place values. So, in the problem we need to approximate 694+7618.

694+7618=8312

We can approximate 8312 based on the provided choices is 8310.

We need to find the radius in order to find the area of the pizza.

Radius of pizza

The area of the pizza

But r=4.5

Thus, the area of the pizza is 20.25  in2.

NOTE:  is used as is since values of pi may vary e.g. 3.14, 3.142, 22/7. Hence we use pi symbol to generalize.