A recipe calls for 2.5 teaspoons of vanilla. 1 teaspoon equals approximately 4.93 mL. Which of the following is the correct amount of vanilla in mL?

We need to find the are of the rectangle from the given case. Letting x represent the width of the rectangle. Then, we can find the area of the rectangle as follows.

Length of rectangle=(x+5)

Width of the rectangle= x

Area of the rectangle, A= Length*width=(x+5)*x

A=x(x+5)

Thus, the area of the rectangle is x(x+5).

The number of boxes is determined by finding the volume of the room divided by the volume of the box.

Number of boxes

The approximate number of boxes that can be stored in the room is 92.

However, the room’s dimensions are 9 ft x 9 ft x 9 ft, and the boxes are 2 ft x 2 ft x 2 ft (unchangeable shape). To determine how many boxes fit along each dimension:

• In the 9 ft length, you can fit\(\frac{9}{2} = 4.5\ boxes\) which means only 4 whole boxes fit along this dimension.
• In the 9 ft width, you can fit 4 whole boxes.
• In the 9 ft height, you can fit 4 whole boxes.

Therefore, the total number of boxes that fit is:

\(4 \times 4 \times 4 = 64\ boxes\)

We are asked to find the number of cups of flour that will be used to make 90 cookies.

Letting x be the number of cups of flour and setting the proportion equation with number of cookies on numerator and number of cups of flour on the denominator. We have

Solve the value of x by cross-multiplying

We convert the mixed fraction into improper fraction in order to carry out multiplication

\(x =\ \frac{9}{4}\ cups\ *\ 90\ cookies\ *\ \frac{1}{36}\ cookies\)

The number of cups of flour needed to make 90 cookies is 5.625 cups, which is equal to 5 5/8 cups(Choice B).

We use the relation 1 L=1000 mL to convert 0.5 L to mL as follows.

Thus, 0.5 L is 500 mL.

To find the greatest number from the given options, we first convert the decimal numbers into fractions.

-0.7 becomes 7/10

-1.3 becomes 13/10

Then, we find the LCM for the denominators of the given fractions. The LCM of 3 and 10 is 30. Now we can multiply each fraction with the LCM.

-2/3*30=-20

-7/10*30=-70

-13/10*30=-39

-4/3*30=-40

Comparing the obtained values from above, -20 is the greatest followed by -39, -40, -70 in that order. The fraction -2/3 gave a value of -20, which was the greatest value. Thus, -2/3 is the greatest value from the given option.

An independent variable is a variable that is manipulated or changed in the experiment. From the given equation, t is an independent variable, which when changed changes the values of the f(t).

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous/rangedata. While a bar graph does just fine even with discrete data.

We are asked to convert kg to pounds using the given relation. Letting x to represent the lb we are looking for.

Nest, we set the proportion with kg in the numerator and lb on the denominator as follows.

We find the value of x by cross-multiplication

The value of x is 110 lb.

The slope represent the ratio between the vertical height to the horizontal length. Let x be the minimum length of the ramp, we can set a proportion with height on the numerator and length on denominator. Then,

Cross-multiply to find the value of x

Thus, the minimum length of the ramp needed is 30 feet to access to a door that is 2.5 feet above the sidewalk.

The mean of a data set is the total scores divided by the number of tests.

Total test scores =100+78+47+84+93+78=480

Number of tests =6

Mean test score =480/6=80

The mean test score is 80.