A class of 28 students has 13 boys and 15 girls. What is ratio of girls to boys in the class?
15:28
13:15
13:28
15:13
Correct Answer : D
a ratio can be converted to a fraction of the form a/b, where b is not equal to zero. In ratio form, to means per.
From the given information, the class has 15 girls and 13 boys. Thus, the ratio of girls to boys becomes:

In ratio form, girls: boys=15:13
Thus, the ratio of girls to boys in a class of 28 students is 15 to 13.
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Related Questions
Correct Answer is B
Explanation
We need to find how many mL are in 2.5 teaspoons. We need to use dimensional analysis to solve this problem as follows.
Converting between teaspoon and mL uses the following conversions:

Or

We want to end up with mL, we utilize the second conversion and set up the following equation.

Thus, 2.5 teaspoons can hold 12.325 mL.
Correct Answer is A
Explanation
to change L to mL we use the following options of interconversions:

Or

Since we are needed to change L to mL, use the second option.

Thus, a bucket can hold 3000 mL which is equal to 3 L.
Correct Answer is D
Explanation
The first three months of the year are January, February, and March. We need to find the total rainfall for these three months from the provided graph.
In the month of January, rainfall is between o and 1, which is halfway. Therefore, rainfall in January is 0.5 inches
On February, rainfall was 1 inch and on March the rainfall was 2 inches. Thus,
Total rainfall = 0.5 inches + 1 inches + 2 inches = 3.5 inches
Correct Answer is C
Explanation
In this problem, we assume the truck carries a whole cargo. Thus, total weight is 516 lb divided by 1/3. Thus,

We change the division sign to product and multiply 516 by reciprocal of 1/3. Then,

The weight of the cargo will be 1548 lbs.
Correct Answer is A
Explanation
The initial step is to convert the decimal numbers into fractions.
4.4 becomes 44/10
4.25 becomes 425/100
Thus, the set of fractions is 9/2, 44/10, 10/3, 425/100. The least common denominator for 2, 10, 3, and 100 is 300, which we use to compare each options given.
9/2*300=1350
44/10*300=1320
10/3*300=1000
425/100*300=1275
From the above, 1350 is the greatest value which corresponds to 9/2. Thus, 9/2 is the greatest value of all the choices given.
Correct Answer is B
Explanation
We are told to find the area of the pizza given its diameter. The pizza is in circular form, and its area is found as:

However, we are not given r, which is the radius of the circle. But we can find it from the given diameter as

Substituting r=8 in the equation of the area of a circle

Thus, the area of the pizza is 64
 in2.
NOTE:Â
 (Pi) remains as a symbol because values of Pi can vary from 22/7 to 3.1415 to 3.14 and so forth.
Correct Answer is A
Explanation
The initial step is to establish the relationship between area of a circle and the radius. The area of the circle is given by the formula

Now, substituting the 49 π
 in2 in place of A in the equation above becomes:

We want to find r, therefore, we rearrange the equation as

Divide both sides by 


Take square root both sides of the equation


The radius of the circle is 7 in, and the circumference of the circle is determined as follows

Substituting the value of r=7 becomes

Thus, the circumference of a circle whose area is 49
 in2 is 14
Â
Correct Answer is B
Explanation
in the given problem, we use the calculator to find 1.3*0.47=0.611
Correct Answer is D
Explanation
we use given information to find how much ammonia is need to make the specified solution.
We are told, one gallon of cleaning solution requires 6 oz of ammonia. In other words, we can express this as:
1 gallon of solution6 oz of ammonia
Or
6 oz of ammonia1 gallon of solution
Since we are needed to find how much ammonia is needed, we use the second option to find how much ammonia is required by 120 gallons of solution.

From the above equation, gallon of solution will cancel, and oz of ammonia is left.
Therefore, the solution will require 720 oz of ammonia.
Correct Answer is A
Explanation
from the given estimations, we can find the actual addition of the numbers and see a trend the student utilizes to find their estimates. The exact sum is as follows
24+190=214
151+319=470
974+1022=1996
From the above evaluation, we can clearly see the students approximates the value in the ones values. So, in the problem we need to approximate 452+5017.
452+5017=5469
We can approximate 5469 based on the provided choices to 5470.
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