A child has collected 50 pennies, 45 nickels, 25 dimes, and 5 quarters. Which of the following charts accurately organizes the number of coins?

The best way to display the frequency of each day of the week when students get up after 8 a.m. is by using a bar graph. Bar graphs are well-suited for representing categorical data, where each day of the week is a separate category, and the height of each bar corresponds to the count or frequency of students waking up late on that specific day.

Note: Histograms, on the other hand, are more appropriate for visualizing continuous or numerical data and are not ideal for categorical data like days of the week.Histograms are useful for understanding the distribution of data, identifying patterns, and assessing the shape of the data distribution, such as whether it's normally distributed, skewed, or has multiple modes.

As you can see below, the Histogram is used to depict a pattern/continuous/rangedata. While a bar graph does just fine even with discrete data.

Correlation of two variables falls into:

Positive correlation: an increase in one variable causes another variable to increase

Negative correlation: an increase in one variable causes another one to decrease

No correlation: a change in one variable does not cause any response in another variable.

From the given choices

Option a is no correlation

Option b is a negative correlation

Option c is a negative correlation

Option d is a positive correlation

When dealing with percent problems, the following is utilized to find the unknown variable.

• Is means equals
• Of means multiply
• What means unknown (variable)

From the problem above, we are looking for the amount of gratuity the couple can leave.

Let t be the amount of gratuity. Translating into an equation, we have

The gratuity is 15% of the total bill, which becomes

Here, of means multiply and we also convert percent into decimal before multiplying.

So, the value of t=5.76

Thus, a couple will leave a gratuity of $5.76, which is about $6.00.

In this problem, we assume the truck carries a whole cargo. Thus, total weight is 516 lb divided by 1/3. Thus,

We change the division sign to product and multiply 516 by reciprocal of 1/3. Then,

The weight of the cargo will be 1548 lbs.

To form an equation from the word problem, first break the given statement into smaller statements.

First, we are given the width of the rectangle as x. We are told, the length is three times width. Mathematically, this means

Length=3*width=3*x=3x

Again, the length is 4 less than 3 times width of the rectangle. Thus, the length of rectangle in terms of width becomes:

Length =3x-4

This is the required equation.

The initial step is to convert the decimal numbers into fractions.

4.4 becomes 44/10

4.25 becomes 425/100

Thus, the set of fractions is 9/2, 44/10, 10/3, 425/100. The least common denominator for 2, 10, 3, and 100 is 300, which we use to compare each options given.

9/2*300=1350

44/10*300=1320

10/3*300=1000

425/100*300=1275

From the above, 1350 is the greatest value which corresponds to 9/2. Thus, 9/2 is the greatest value of all the choices given.

in the given problem, we use the calculator to find 1.3*0.47=0.611

We use 1 L =1000 mL to convert between the two units. The conversion fractions of interconverting are:

And

Since we want to end up with millimeters, the second conversion is used in converting L to mL as:

Thus, 0.5 L is equivalent to 500 mL.

we need to form a mathematical expression from the given word problem.

Let the number be x.

Twice a number=2x

Five less than twice a number=2x-5

So the mathematical express from the word problem is 2x-5

the median of a data set is the element that is found on the middle position. It is found by organizing the elements from the smallest to largest.

The data set above arranged from the smallest to largest is:

11, 12, 12, 12, 13, 14, 17, 17, 18, 22, 26

The number of elements is odd and the median is found in the (N+1)/2 th position. Here N=11, and the median falls in (11+1)/2=12/2=6 th position.

The element 14 falls in the 6th position, which is our median of the given data set.