A bucket containing 3 3/5 gallons of water is 2/3 full. How many gallons of water is in one fully filled bucket?

The SI units of measuring length is meter. However, a meter can be a large unit or small quantity depending what is being measured. Therefore, derived units of meters are used to measure the length of an object. In our case, centimeters is the appropriate unit to measure the width of the window.

percentages are fractions with denominator equal to 100. Then, in decimal form:

The decimal form of 67.9% is 0.679.

To answer this question, we need to convert the numbers into a similar form. Converting decimal numbers into fraction is appropriate to finding the greatest number.

-0.9 becomes 9/10

-1.9 becomes 19/10

Now we find the LCM of the denominators of the four fractions. The LCM of 5, 10 and 3 is 30. Multiply each fraction with the LCM to compare the fractions.

-3/5*30=-18

-9/10*30=-27

-19/10*30=-57

-8/3*30=-24

The greatest number is -18, meaning -3/5 is the greatest number.

We are tasked to find the unknown values of x in the given equation.

First, we add 8 to both sides of the equation.

Next, we apply the absolute rule:

If   , a>0, then u=a or u=-a

From our resulting equation, a=14, which is greater 0. Then, the first condition (u=a) becomes

Solving for x

The second condition (u= -a) becomes

Solving for x

Thus, the value of x is 4 or -3

This problem asks us to compare the number of dimes to nickels.

If we let p be number of pennies in the bottle. Then,

Number of quarters in the bottle = 4p

Number of nickels in the bottle = 2p

Number of dimes in the bottle =7(2p)=14p

To find the number of dimes the child has than nickels, we use the ratio:

\(\frac{Dimes}{nickels} =\frac {14p}{2p}\ =\ 7\)

Thus, there are 7times as many dimes as nickels in the box.

the mean of a data set is the sum of the scores divided by the number of tests.

Total test scores =99+93+67+ 48+ 92+ 87=486

Number of tests =6

Mean test score =486/6=81

The mean test score is 81.

notice that the question compares the cup of flour and the cup of milk. We can therefore set up our ratios as cup of floorcup of milk. If we let the x be the number of cups of milk needed, then

As a mixed fraction, 70/3 becomes 23 1/3, which represents the number of cups of milk needed to make a big batch of 5 cups.

We are asked to convert kg to pounds using the given relation. If we let x to represent the lb we are asked to find, we set the proportion equation with kg on numerator and lb on the denominator as follows.

The equivalent value of 55kg is 121 lb.

we are asked to find the amount of milk in mL using the given information.

If we let x represent the amount of milk in mL, we set up a proportion with number of teaspoons on the numerator and amount in mL in the denominator.

A recipe of 3.4 teaspoons is equal to 17.0 mL.

The number of boxes to fit the room is found as volume of the room divided by the volume of the box.

Number of boxes:

\(\frac{volume\ of\ the\ room}{volume\ of\ the\ box} = \frac{12ft\ *\\ 12ft\ *\ 12ft}{2.5ft\ *\ 2.5t\ *\ 2.5ft}\ =\ 110.592\)

The approximate number of boxes that can be stored in the room is approximately 111 square feet.