A nurse is preparing to administer mannitol 0.2 g/kg IV bolus over 5 min as a test dose to a client who has severe oliguria. The client weighs 198 lb. What is the amount in grams the nurse should administer? (Round the answer to the nearest whole number. Use a leading zero if it applies. Do not use a trailing zero.)
The Correct Answer is ["18"]
The client weighs 198 lb, which is equivalent to (198 ÷ 2.2 = 90kg.
Therefore, the amount of mannitol for the test dose is 0.2 g/kg x 90 kg = 18 g. The nurse should administer 18 g of mannitol IV bolus over 5 min as a test dose to the client who has severe oliguria.
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Related Questions
Correct Answer is B
Explanation
- A is incorrect because massaging bony prominences on the client's left side can increase the risk of skin breakdown and pressure ulcers. The nurse should avoid applying pressure to areas with impaired circulation or sensation.
- B is correct because supporting the client's left arm on a pillow while sitting can prevent edema, contractures, and nerve damage. The nurse should also encourage the client to perform active and passive range of motion exercises on their left arm.
- C is incorrect because positioning the bedside table on the client's left side can discourage the client from using their right side, which can lead to neglect and learned nonuse. The nurse should position the bedside table on the client's right side and encourage them to reach for items with their right hand.
- D is incorrect because placing the client's cane on their left side while ambulating can cause instability and falls. The nurse should place the cane on the client's right side and instruct them to move their left leg and cane together, followed by their right leg.
Correct Answer is A
Explanation
Choice A rationale:
The nurse should include the statement, "Use a product with DEET on your skin and clothes when you are walking in a wooded area," in the educational program on Lyme disease. DEET is a widely used insect repellent effective against ticks. It is recommended to prevent tick bites in wooded and grassy areas. The rationale behind this choice is to educate the public about practical measures to reduce the risk of Lyme disease. DEET repels ticks, reducing the chances of tick attachment and, consequently, the transmission of Lyme disease.
Choice B rationale:
The statement, "Symptoms of Lyme disease appear 2 days after being bitten by an infected tick," is incorrect. The incubation period for Lyme disease can vary from 3 to 30 days after the tick bite. Symptoms usually appear within 3 to 14 days but can take longer to manifest. Providing inaccurate information can lead to misunderstanding and inadequate preventive measures.
Choice C rationale:
The statement, "Remove embedded ticks by squeezing the body with tweezers," is incorrect. Improper removal of ticks, such as squeezing the body, can lead to the injection of tick fluids into the host, increasing the risk of disease transmission. The correct method for tick removal is to use fine-tipped tweezers to grasp the tick as close to the skin's surface as possible and pull upward with steady, even pressure. This helps ensure the tick is removed entirely and reduces the risk of infection.
Choice D rationale:
The statement, "If bitten by a tick, testing for Lyme disease should occur within 2 weeks," is incorrect. Testing for Lyme disease immediately after a tick bite is not recommended because it takes time for the body to produce antibodies detectable by the tests. Testing too early can yield false-negative results. Healthcare providers may recommend testing if symptoms develop, but waiting for a few weeks after the bite increases the accuracy of the test results.
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